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2x+0.25x^2=5x
We move all terms to the left:
2x+0.25x^2-(5x)=0
We add all the numbers together, and all the variables
0.25x^2-3x=0
a = 0.25; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·0.25·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*0.25}=\frac{0}{0.5} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*0.25}=\frac{6}{0.5} =12 $
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